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# If a,b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c +d) satisfies the relation : (A) 0 = M = 1 (B) 1 = M = 2 (C) 2 = M = 3 (D) 3 = M = 4

Arun Kumar IIT Delhi
7 years ago
$(a+b+c+d)\geqslant 2\sqrt{(a+b)(c+d))} \\=>M\leqslant 1$

Arun Kumar
IIT Delhi