If a b c d are in GP and a^x=b^y=c^z=d^u then x,y,z,u are in HP. how please explain

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Arun · Answer

On solving we get y=2xz/(x+z)which means x,y,z are in H.P z =c y =b x = acAlso a 2 a,b,c are in GP then y Regards Arun (askIITians Forum expert)

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If a b c d are in GP and a^x=b^y=c^z=d^u then x,y,z,u are in HP. how please explain

If a b c d are in GP and a^x=b^y=c^z=d^u then x,y,z,u are in HP. how please explain

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If a b c d are in GP and a^x=b^y=c^z=d^u then x,y,z,u are in HP. how please explain

If a b c d are in GP and a^x=b^y=c^z=d^u then x,y,z,u are in HP. how please explain

1 Answers

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