if 13 99 is divided by 81 then the remainder is divisible by - i) 5 ii) 3 iii) 7 iv) 11 .

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Krishnaprasad · Answer

We can write 13 = 4x+1, where x=3; We know that 81 is equal to 3 4 =x 4 13 99 = (4x+1) 99 = 99 C 0 (4x) 99 + …...................... + 99 C 3 (4x) 3 + 99 C 2 (4x) 2 + 99 C 1 (4x) 1 +1 All the terms except the last two will get cancelled when 13 99 is divided by 81. So, if we divide the last two terms by 81, we will get the remainder required. 99*12 +1 = 1189 which on division with 81 gives remainder 55. So the remainder is divisible by 5 and 11

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if 13 99 is divided by 81 then the remainder is divisible by - i) 5 ii) 3 iii) 7 iv) 11 .

if 13⁹⁹is divided by 81 then the remainder is divisible by -
i) 5 ii) 3 iii) 7 iv) 11 .

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if 13 99 is divided by 81 then the remainder is divisible by - i) 5 ii) 3 iii) 7 iv) 11 .

if 1399 is divided by 81 then the remainder is divisible by - i) 5 ii) 3 iii) 7 iv) 11 .

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if 13⁹⁹is divided by 81 then the remainder is divisible by -
i) 5 ii) 3 iii) 7 iv) 11 .