I got a question...Plzz answer....Q.34.-If1of diagonal of square is along line x=2y &one of its vertex is (3,0),then it`s sides though this vertex are given by equations...

Dear Student,

Let A (3,0) and let AB (above) and AC (below) be the two vertices from A.

Now the slope of perpendicular from A on x = 2y will be -2. and let this perpendicular be AP having slope = -2.

Now, Slope(AP) – slope(AB) = 1 (45 degree).
Therfore, slope (AB) = -3,
Therfore equation of AB will be y = (-3)(x-3) or 3x + y – 9 =0. ---- (1)

Similarlly, Slope of (AC) – Slope(AP) = 1 (45 degree),
Thuse, slope (AC) = 3,
Therefore equation of AC will be y = (3)(x-3) or y – 3x + 9 = 0. ------ (2)

Clearly, equation (1) and (2) are penpendicular, but none of the options has two perpendicular equations, hence they are incorrect options.

Thanks.