
Grade 12IIT JEE Entrance Exam
how preperation for iit jee advanced is different from cbse 10+2
how preperation for iit jee advanced is different from cbse 10+2

Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-
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