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How much water must be added in 900ml of 0.1M CH3COOH solution to triple its degree of dissociation(Assume a

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3 years ago

## Answers : (1)

Arun
25768 Points
```							Dissociation of acetic acid occurs as -CH3COOH  CH3COO- + H+ Initial degree of ionization is calculated by -α = √(Ka/C1)α = √(1.8×10^-5 / 0.2)α = 9.5×10^-3 Later degree of dissociation is doubled, 2α = 19×10^-3 Later conc is calculated by -C = Ka / (2α)^2C = 1.8×10^-5 / (19×10^-3)C = 0.05 M New volume of solution -V2 = C1V1 / C2V2 = 300×0.2 / 0.05V2 = 1200 ml Water to be added -∆V = V2 - V1∆V = 1200 - 300∆V = 900 ml Therefore, total 900 ml water need to be added.
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7 months ago
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