Refer to the site -
jeemain.nic.in
It says that the Ministry of Human Resource Development, Government of India has notified following two changes in the JEE pattern from 2017:
1. There shall be no weightage for the 12th class marks in calculating the ranks in the JEE (Main) examination,
2. For the candidates to qualify for the admission in the IITs/NITs/IIITs and such other CFTIs whose admissions are based on the JEE (Advanced)/JEE(Main) ranks, they should have secured at least 75% marks in the 12th class examination, or be in the top 20 percentile in the 12th class examination conducted by the respective Boards. For SC/ST students the qualifying marks would be 65% in the 12th class examination.
However, if you don't get admission in desired college, do not get disoriented. Rather try and search about the reputation and the placements offered by some private universities. You can select B Tech.
B Tech is one of the most popular courses, always in demand in India. Students prefer this course with an idea of securing a well paid job after the completion of their professional degree course. So you can select any branch of engineering depending upon your interest among CSE, Mechanical, Electronics, Civil, Aerospace, Biotechnology, Food Technology, Biomedical Engineering, Information Technology, Chemical Engineering, Automobile Engineering, Electronics and Computer Engineering or any other.
So it is advisable if you earn your degree from a well known university that provides prime placement opportunity, outstanding industrial exposure and professional enhancement training.
I can enlist some universities for your help -
Lovely Professional University,
Manav Rachna University,
Sharda University etc.
which offer excellent learning atmosphere to their students.
I hope it helps.
Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-
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