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Grade: 11
        Given vertices A(1,1) B(4, - 2 )and C (5,5) of a triangle then the equation of the perpendicular drop from C to the interior bisector of the angle A is
2 years ago

Answers : (2)

Gowtham
40 Points
							
let the angular bisector throught A meets the side BC at X
the line AX divides the side BC in the ratio of AC : AB
now we can find the point X
so now we can get the equation of AX
let the perpendicular dropped from C is CF
as AX and CF are perpendicular
slope of AX* slope of CF=-1
we have point C and slope of CF
so now we can find equation of CF
 
 
2 years ago
Divyansh
13 Points
							
 
let the angular bisector throught A meets the side BC at X
the line AX divides the side BC in the ratio of AC : AB
now we can find the point X
so now we can get the equation of AX
let the perpendicular dropped from C is CF
as AX and CF are perpendicular
slope of AX* slope of CF=-1
we have point C and slope of CF
so now we can find equation of CF
one year ago
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  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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