for what value of non negative integer a will thesystem x²-y²=0,(x-a)²+y²=1 have exactly three real solutions
Vishl , 7 Years ago
Grade 12
IIT JEE Entrance Exam> for what value of non negative integer a ...
1 Answers
Arun
Last Activity: 4 Years ago
given = x²-y²=0
(x-k)²+y²=1 => x²- 2kx + k²+y² =1
by adding this two equations we will get,
2x² - 2kx + k²= 0
and now we all know that if the discriminant is zero i.e., b² + 4ac=0 then the quadratic equation has one solution.
Then,
4k² - 8k = 0
4k²=8k
4k = 8
k = 8/4 = 2
so the correct answer is a) 2
Hope you understand
Thanks and regards
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