0

Guest

Courses New

For any real numbers x and y ,coax =cosy ,implies =2nπ±y, where n belongs to Z In this solution sinx+y/2=0 How x+y/2=nπ? please explain this steps

For any real numbers x and y ,coax =cosy ,implies =2nπ±y, where n belongs to Z 
In this solution sinx+y/2=0
How x+y/2=nπ?  please explain this steps

Grade:11

2 Answers

Aditya Gupta
2081 Points
5 years ago
you are asking how does sin(x+y/2)=0 imply x+y/2=nπ.
let  x+y/2=z
then sinz=0 but graph of sinx shows that it is zero if and only if z is an integral multiple of pi.
so z= npi
or  x+y/2=nπ
manantomar
19 Points
5 years ago
 
you are asking how does sin(x+y/2)=0 imply x+y/2=nπ.
let  x+y/2=z
then sinz=0 but graph of sinx shows that it is zero if and only if z is an integral multiple of pi.
so z= npi
or  x+y/2=nπ
This is CORRECT

Think You Can Provide A Better Answer ?

Other Related Questions on IIT JEE Entrance Exam

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More