For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is:
(A) 4R
(B) 5R
(C) 400R
(D) 2000R

Question

For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is: (A) 4R (B) 5R (C) 400R (D) 2000R

Vikas TU · Answer

Dear student Variation of k with temperature is given by log K = del S /R - del H /RT = 4.0 - 2000/T On comparison delS /R = 4 del S = 4R

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For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is: (A) 4R (B) 5R (C) 400R (D) 2000R

For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is:
(A) 4R
(B) 5R
(C) 400R
(D) 2000R

For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is:
(A) 4R
(B) 5R
(C) 400R
(D) 2000R

1 Answers

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For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is: (A) 4R (B) 5R (C) 400R (D) 2000R

For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is:(A) 4R(B) 5R(C) 400R(D) 2000R

For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is:(A) 4R(B) 5R(C) 400R(D) 2000R

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For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is:
(A) 4R
(B) 5R
(C) 400R
(D) 2000R

For an isomerisation reaction A ⇔ B, the temperature dependence of equilibrium constant is given by ln K = 4 – (2000/T). The value of ∆Sº at 400 K is:
(A) 4R
(B) 5R
(C) 400R
(D) 2000R