Grade 11IIT JEE Entrance Exam

Find the eccentric angles of the extrimities of latus recta of the ellipse x^2/a^2+y^2/b^2=1(a>b)

Manish

9 Years agoGrade 11

2 Answers

Piyush Kumar Behera

9 Years ago

The x coordinate of latus rectum is the x coordinate of the ends of the latus rectum = $\pm$ ae

And the parametric coordinates of ellipse are (acos $\theta$ ,bsin $\theta$ )

Now,if the eccentric angle of ends of latus rectum is $\theta$ then acos $\theta$ =+ae

$\theta$ =cos^-1e

Manish

9 Years ago

use the formula

this is the most imp thing you need to know...............

$x=acos\theta y=bsin\theta \frac{y}{x}=\frac{b}{a}tan\theta$

tan $\theta$ =ay/bx

where ends of latus recta are ( $\pm$ ae,b²/a)

i.e x=ae, y=b²/a

$\therefore$ $tan\theta =(a*b^{2}/a)/(b*ae) =b/ae$

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Find the eccentric angles of the extrimities of latus recta of the ellipse x^2/a^2+y^2/b^2=1(a>b)

Manish

2 Answers

Piyush Kumar Behera

Manish

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