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        Find the eccentric angles of the extrimities of latus recta of the ellipse x^2/a^2+y^2/b^2=1(a>b)
2 years ago

Piyush Kumar Behera
432 Points
							 The x coordinate of latus rectum is the x coordinate of the  ends of the latus rectum =$\pm$aeAnd the parametric coordinates of ellipse are  (acos$\theta$,bsin$\theta$) Now,if the eccentric angle of ends of latus rectum is $\theta$ then acos$\theta$=+ae$\theta$=cos-1e

2 years ago
Manish
37 Points
							use the formulathis is the most imp thing you need to know...............$x=acos\theta y=bsin\theta \frac{y}{x}=\frac{b}{a}tan\theta$tan$\theta$=ay/bxwhere ends of latus recta are ($\pm$ae,b2/a)i.e x=ae, y=b2/a$\therefore$$tan\theta =(a*b^{2}/a)/(b*ae) =b/ae$

2 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions