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Find the domain of the functions given in the attached image.

Vishnu MK , 9 Years ago
Grade 12
anser 1 Answers
Riddhish Bhalodia

Last Activity: 9 Years ago

1.
The first square root requiresx \leq 0but if x=0 then the second term denominator goes to zero and hence the domain is
x < 0

2.
The denominator must not be zero and the whole rational function must be positive
when x<0,|x| = -x and then if x<-1 then both numerator and denominator becomes neative and hence making the rational function positive, secondly for 1>x>=0 the denominator is positive which works too
Hence the domain is
x \in (-\infty,-1) \cup [0,1)

3.
we deal with quadratic inside square roots
first one will give
x^2-|x| -2 = (|x|-2)(|x|+1) \geq 0
|x| is always positive therefore what remains is
(|x|-2)\geq 0 \Rightarrow x \in (-\infty,-2]\cup[2,\infty)
Now the second quadratic (taking the -ve)
x^2 - 16 = (x-4)(x+4) \leq 0
\Rightarrow x \in [-4,4]
taking the intersection of both the subdomains we get the domain as
x \in [-4,-2]\cup[2,4]

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