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`        Find: Centre of mass of given system.The figure lies in a 3d space  `
8 months ago

Pooja
127 Points
```							We write the coordinates of each particle
```
8 months ago
Pooja
127 Points
```							Sorry I accidentally posted earlier answer without completing it and don`t know to delete itWe write the co ordinates of each particleLet us assume the distance of each masa particle from axis is aFor each particle of mass m(a,a,0) , (a,0,0) , (0,0,0) , (0,a,0)For each particle of mass 2m(a,a,a) , (0,0,a) , (a,0,a) , (0,a,a)COM is given by={m(a,a,0) + m(a,0,0) + m(0,0,0) + m(0,a,0)+2m(a,a,a) + 2m(0,0,a) + 2m(a,0,a) +                    2m(0,a,a)}÷12=(6a , 8a , 8a )÷12= (a/2 , 2a/3, 2a/3)
```
8 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions