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f(x)=y=3x-1
switching the variables to find the inverse function;
x=3y-1
y=(x+1)/3
thus f-¹(x)=(x+1)/3
g(f-¹(x))=f-¹(x)(f-¹(x)-1)
=((x+1)/3)*((x+1)/3)-1)
= ((x+1)/3)*((x+1–3)/3)
= ((x+1)(x-2))/9
= (x^2 - x - 2)/9
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