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        explain this question please “a disc is freely rotating with an angular speed w on a smooth horizontal plane. it is hooked at a rigid peg P and rotates about P without bouncing. its angular speed after the impact will be equal to?”
one year ago

Arun
19061 Points
							Dear Student ,Here , in this case the angular speed of the disc is ω which is freely rotating on a smooth horizontal plane .It is hooked at a rigid peg about P without bouncing when the disc collides with the peg then after collision , let the angular speed be ω' .Now the whole case takes time = t and here the change in angular speed in time t is angular acceleration α .Now angular speed after collision will be ,ω'=(ω+αt )+atrNow this change in angular acceleration is due to sum of rotational motion and translational motion of the peg.Here ω+αt =is due to the rotational motion and atr =is due to the linear translational motion where r is the radius of the disc.Hope this helps you .

one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions