MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
explain this question please “a disc is freely rotating with an angular speed w on a smooth horizontal plane. it is hooked at a rigid peg P and rotates about P without bouncing. its angular speed after the impact will be equal to?”
9 months ago

Answers : (1)

Arun
15880 Points
							
Dear Student ,
Here , in this case the angular speed of the disc is ω which is freely rotating on a smooth horizontal plane .It is hooked at a rigid peg about P without bouncing when the disc collides with the peg then after collision , let the angular speed be ω' .
Now the whole case takes time = t and here the change in angular speed in time t is angular acceleration α .
Now angular speed after collision will be ,
ω'=(ω+αt )+atrNow this change in angular acceleration is due to sum of rotational motion and translational motion of the peg.Here ω+αt =is due to the rotational motion and atr =is due to the linear translational motion where r is the radius of the disc.
Hope this helps you .
9 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 1,590 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details