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dx÷root of 2ax-x 2 =a n sin -1 [x÷a-1].How can i solve this by using dimensions??

dx÷root of 2ax-x2=ansin-1[x÷a-1].How can i solve this by using dimensions??
 

Grade:11

1 Answers

Deepak Kumar Shringi
askIITians Faculty 4405 Points
2 years ago
not able to understand the query..please click an image and upload it.. i will be happy to solve your doubt

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