Grade 12th passIIT JEE Entrance Exam
Displacement of a partial is given by S=3t^3+7t^2+5t+8 . acceleration of the partial is
1 Answer
Prashant
Displacement =3t^3+7t^2+5t+8Therefore on differentiating Vel=9t^2+14t+5Differentiating again we will get accelerationAcc=18t+14
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