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Grade 12IIT JEE Entrance Exam

Determine the molar mass of a gas if its pressure is to fall to one-half of its value in a vertical distance of
one meter at 298 K.

Profile image of Anish Ambavat
7 Years agoGrade 12
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1 Answer

Profile image of Arun
7 Years ago
 

ρg(h1-h2)= P-P/2

ρ=PM/RT

h1-h2=1

R=8.314

g=9.8

T= 298

M=RT/2g=8.314*298/2*9.8

M=126.4

 

Regards

Arun (askIITians forum expert)

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