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`        Consider a car moving on a straight road with a speed of 100 metre per second the distance at which the car can be stop is UK is equals to 0.5`
2 years ago

Shashank
21 Points
```							Given :u = 100 m/sv = 0 m/suk = 0.5 Solution :Fk = uk * Nma = uk * mgma = uk * mga = 0.5 * 10 m/s2a = 5 m/s2 v = u + at0 = 100 + (-5)tt = 100/5 st = 20 s s = ut + ½ at2s = (100)(20) + ½ (-5)(20)2 ms = 2000 - ½ (2000) ms = 2000 – 1000 ms = 1000 m
```
2 years ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions