Grade 12IIT JEE Entrance Exam

Calculate % yield of the reaction if 200g KHCO3 produces 22g of Co2 upon strong heating.

Kiran Alex Johnson

11 Years agoGrade 12

3 Answers

Naveen Kumar

11 Years ago

2KHCO3.........>...........K2CO3.+...........CO2.+........H2O
200g....................................................22g

According to the reaction, 2 moles ofKHCO3 should give 1 mole ofCO2.
i.e......................................2*100g.KHCO3.................................1*44gCO2 for 100% yield.
i.e. 200gKHCO3 should produce.................44g of CO2
but 200g.....................................................22g of CO2
so % yield={actual yield/Theoretical yield}*100
...............={22/44}*100=50%

Pranjul mishra

7 Years ago

As masses are given so when we will calculate the moles

Molar mass of khco3 = 100

Moles are =200/100=2 moles

Moles of co2=2 according to given data but,

The reaction is as follows

2khco3---->k2co3+co2+h20

So according to reaction 2moles khco3 gives 1 mole co2 so % yeild = given weight /actual weight *100=22/44*100=50%

Hope it would be helpful ☺️☺️

Hope it would be helpful

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7 Years ago

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