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# Calculate % yield of the reaction if 200g KHCO3 produces 22g of Co2 upon strong heating.

Naveen Kumar
6 years ago
2KHCO3.........>...........K2CO3.+...........CO2.+........H2O
200g....................................................22g

According to the reaction, 2 moles ofKHCO3 should give 1 mole ofCO2.
i.e......................................2*100g.​KHCO3.................................1*44gCO2 for 100% yield.
i.e. 200gKHCO3 should produce.................44g of CO2
but 200g.....................................................22g of CO2
so % yield={actual yield/Theoretical yield}*100
...............={22/44}*100=50%
Pranjul mishra
15 Points
one year ago
As masses are given so when we will calculate the moles
Molar mass of khco3 = 100
Moles are =200/100=2 moles
Moles of co2=2 according to given data but,
The reaction is as follows
2khco3---->k2co3+co2+h20
So according to reaction 2moles khco3 gives 1 mole co2 so % yeild = given weight /actual weight *100=22/44*100=50%

Hope it would be helpful ☺️☺️