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`        Calcium Crystallizes in a cubic unit cell with density 3.2g/cc. Edge length of the unit cell is 437 pm. If the metal is melted, density of the molten metal was found to be 3g/cc. What will be the percentage of empty space in the melt?`
one year ago

Yugank Sharma
14 Points
```							Firstly by solving in solid state we will get Z=4 which means the lattice is FCC.Now when the metal melts by keeping the values in the density formula we can calculate the value of Z/a^3 and putting this in the formula for packing efficiency keeping the radius same as for solid state we can get the %occupied state. Subtarcting it from 100 we get our required answer.
```
one year ago
Sahil
12 Points
```							Here M=3.2V THEN 3=3.2V/Vf Vf=1.066VThen we know that 0.74 occupied space So ,0.74/1.066=69%100-69=31% ✓✓✓✓✓
```
3 months ago
Vikas TU
11140 Points
```							Dear stuent The ans of sahil is correct , Hope this will clear your doubt. Good Luck …...............Cheers
```
2 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions