MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
Calcium Crystallizes in a cubic unit cell with density 3.2g/cc. Edge length of the unit cell is 437 pm. If the metal is melted, density of the molten metal was found to be 3g/cc. What will be the percentage of empty space in the melt?
one year ago

Answers : (3)

Yugank Sharma
14 Points
							
Firstly by solving in solid state we will get Z=4 which means the lattice is FCC.
Now when the metal melts by keeping the values in the density formula we can calculate the value of Z/a^3 and putting this in the formula for packing efficiency keeping the radius same as for solid state we can get the %occupied state. Subtarcting it from 100 we get our required answer.
 
one year ago
Sahil
12 Points
							
Here M=3.2V
 THEN 
3=3.2V/Vf
 
Vf=1.066V
Then we know that 0.74 occupied space 
So ,0.74/1.066=69%
100-69=31% ✓✓✓✓✓
 
3 months ago
Vikas TU
11140 Points
							
Dear stuent 
The ans of sahil is correct , 
Hope this will clear your doubt. 
Good Luck …...............
Cheers 
2 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details