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Bond energy of H-H is 104 kcal/mol,X-X is 60 kcal/mol,H-X is 101 kcal/mol
Electronegativity of H is 2.1 What is the electro negativity of X?

Profile image of revathy
8 Years agoGrade 12
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1 Answer

Profile image of Arun
8 Years ago
Dear Student
 
Actual Bond energy \Delta = EH-X – \sqrtEH-H * EX-X
 = 101 – \sqrt104* 60
 = 22.01 Kcal/mol
 
Electro negativity deiiference is
XH – Xx  = 0.208 \sqrt\Delta
2.1 –  Xx  = 0.208 * \sqrt22.01
 Xx  = 1.12
hence electronegativity of unknown atom is 1.12
 
Regards
Arun (askIITians forum expert)