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`        Body of mass 1 kg initially at rest explodes and breaks into three fragments of masses in the ratio 1:1: 3. The two pieces of equal masses fly of perpendicular to each other with a speed of 30m/s each. What What is the velocity of heavier fragment`
9 months ago

Arun
21951 Points
```							 The figure will make clear that movement of COM of the two equally weighed particles is along the dotted axiz (please consult the figure) which is at an angle 45° from both the particles m1 and m2. Now, we consider it as a single particle of mass 400gms (ATQ) [mass of m1+m2] moving with a velocity of [30 cos45°] along the dotted line.  So, the third particle (m3) which is of mass thrice to the original m1 and m2, and 3/2 of the mass of their centre of mass, must move along the red line with a velocity that balances the net momentum of the rest two particles to zero. Now acc. to Law of Conserv. of Momentum, Let, m* and v* be the mass and velocity of centre of mass of m1 and m2 respectively.m3.v3=m*.v*.6 is the mass of heavier particle..4 is the mass of COM of the two lighter particles.v3=Unknownv*= 30cos45° Solving the above eqn using the given statistics, we getv3=10√2which is our required answer RegardsArun
```
9 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions