asinx+bcosx=p and acosx+bsinx=q,then (ap-bq)=?,I have attempted this question with various method but failed,please give detailed explanation?

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Abhiram · Answer

ap = a 2 sinx+ab cosx (multiplied both sides of p with a) bq = ab cosx+b 2 sinx (multiplied both sides of q with b) ap-bq= a 2 sinx+ab cosx-(ab cosx+b 2 sinx) => ap-bq= a 2 sinx-b 2 sinx= sinx(a 2 -b 2 )

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asinx+bcosx=p and acosx+bsinx=q,then (ap-bq)=?,I have attempted this question with various method but failed,please give detailed explanation?

asinx+bcosx=p and acosx+bsinx=q,then (ap-bq)=?,I have attempted this question with various method but failed,please give detailed explanation?

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asinx+bcosx=p and acosx+bsinx=q,then (ap-bq)=?,I have attempted this question with various method but failed,please give detailed explanation?

asinx+bcosx=p and acosx+bsinx=q,then (ap-bq)=?,I have attempted this question with various method but failed,please give detailed explanation?

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