Samyak Jain
Last Activity: 5 Years ago
f(x) dx = { f(x) + f(–x) } dx So, given integral becomes
{1 / ( [x] + [sinx] + 4) + 1 / ( [–x] + [–sinx] + 4) } dx = {1 / ( [x] + [sinx] + 4)} dx + 1 / ( [–x] + [–sinx] + 4) } dx Let us take first part of the integral.
{1 / ( [x] + [sinx] + 4)} dx = {1 / ( [x] + [sinx] + 4)} dx + {1 / ( [x] + [sinx] + 4)} dx = {1 / ( 0 + 0 + 4)} dx + {1 / ( 1 + 0 + 4)} dx for sinx belongs to (0,
/2), [sinx] = 0 and x belongs to (0,1), x = 0 while x belongs to (1,
/2), x = 1.
= (1/4)(1 – 0) + (1/5)(
/2 – 1) =
/10 + 1/4 – 1/5 =
/10 + 1/20
=
(1/20)(2 + 1) ….....(1)
Now,
[x] + [–x] = –1 [–x] = –1 – [x] and [–sinx] = –1 – [sinx]. [–x] + [–sinx] + 4 = –1 – [x] –1 – [sinx] + 4 = 2 – [x] – [sinx].
Take second part of the integral.
1 / ( [–x] + [–sinx] + 4) } dx = 1 / ( 2 – [x] – [sinx]) } dx = {1 / ( 2 – [x] – [sinx])} dx + {1 / ( 2 – [x] – [sinx])} dx = {1 / ( 2 – 0 – 0)} dx + {1 / ( 2 – 1 – 0)} dx [Reason is similar as above.]
= (1/2)(1 – 0) + (1/1)(
/2 – 1) = 1/2 +
/2 – 1
=
/2 – 1/2 =
(1/2)( – 1) …........(2)
Given definite integral is : (1/20)(2
+ 1) + (1/2)(
– 1) = (1/20)(2
+ 1 + 10
– 10)
= (1/20)(12
– 9)
=
(3/20)(4 – 3) is the answer.