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An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically by additional 46 cm. What will be length of the air column above mercury in the tube now?

An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically by additional 46 cm. What will be length of the air column above mercury in the tube now?

Grade:

2 Answers

Saurabh Kumar
askIITians Faculty 2411 Points
6 years ago
For an isothermal condition, P1V1 = P2V2
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Yash Chourasiya
askIITians Faculty 256 Points
9 months ago
Dear Student

Using isothermal process conditions

We haveP1​V1 ​= P2​V2​
Thus
8AP0 ​= PAx(A is the cross-sectional area of the tube and P is the pressure in the tube when it is raised)
ThusP = 8Po/x​​
Thus equating the pressure at points 1 and 2 we get


643-1358_Untitled.png

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya

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