An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically by additional 46 cm. What will be length of the air column above mercury in the tube now?

For an isothermal condition, P1V1 = P2V2

Dear Student

Using isothermal process conditions

We haveP₁​V₁ ​= P₂​V_2​
Thus
8AP₀ ​= PAx(A is the cross-sectional area of the tube and P is the pressure in the tube when it is raised)
ThusP = 8P_o/x​​
Thus equating the pressure at points 1 and 2 we get




I hope this answer will help you.
Thanks & Regards
Yash Chourasiya