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An aluminum wire of diameter 4mm carries a current of 4.4 A.The current density is
So here we've an aluminum wire of thickness 4mmThus, r=2mm and I=2.2ACurrent Density,J=I/AA= πr²= π(2x10^-3)²J= (2.2/π(2x10^-3)²) =1.75x0^5 A/m²
So here we've an aluminum wire of thickness 4mm
Thus, r=2mm and I=2.2A
Current Density,
J=I/A
A= πr²= π(2x10^-3)²
J= (2.2/π(2x10^-3)²)
=1.75x0^5 A/m²
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