An aeroplane of mass M requires a speed v for take off. The length of the runway is s and the coefficient of friction between the tyres and the ground is u. Assuming that the plane accelerates uniformly during the take off, the minimum force required by the engine of the plane for take off is ?

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Saurav · Answer

Let the force applied be F then net force on aeroplane will be F-uMg Therefore accleration will be a= (F-uMg)/M Now apply v square-u square =2as here u is initial velocity=0 Hope that helps u Don't forget to approve :)

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An aeroplane of mass M requires a speed v for take off. The length of the runway is s and the coefficient of friction between the tyres and the ground is u. Assuming that the plane accelerates uniformly during the take off, the minimum force required by the engine of the plane for take off is ?

An aeroplane of mass M requires a speed v for take off. The length of the runway is s and the coefficient of friction between the tyres and the ground is u. Assuming that the plane accelerates uniformly during the take off, the minimum force required by the engine of the plane for take off is ?

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An aeroplane of mass M requires a speed v for take off. The length of the runway is s and the coefficient of friction between the tyres and the ground is u. Assuming that the plane accelerates uniformly during the take off, the minimum force required by the engine of the plane for take off is ?

An aeroplane of mass M requires a speed v for take off. The length of the runway is s and the coefficient of friction between the tyres and the ground is u. Assuming that the plane accelerates uniformly during the take off, the minimum force required by the engine of the plane for take off is ?

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