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An aeroplane is flying in the horizontal direction with a velocity 600 km/hr at a height 1960 m. When it is vertically above a point A on the ground, a body is droppd from it. The body strikes a ground at point B. The distance AB is equal to? An aeroplane is flying in the horizontal direction with a velocity 600 km/hr at a height 1960 m. When it is vertically above a point A on the ground, a body is droppd from it. The body strikes a ground at point B. The distance AB is equal to?
The body has a horizontal component of velocity ux=600km/hr and no vertical component uy=0.Also it has no horizontal component of acceleration ax=0 and ay=g.The horizontal distance x=uxt.We have to find out t.h=uyt+gt2/2=gt2/2or,t2=2h/gor,t=20s=1/180 hrSo x=uxt=600/180=10/3 km=3.33kmSo the distance AB=root(h2+x2)=root(19.62+3.332)=19.8 kmHope this helps.
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