Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
An aeroplane is flying in the horizontal direction with a velocity 600 km/hr at a height 1960 m. When it is vertically above a point A on the ground, a body is droppd from it. The body strikes a ground at point B. The distance AB is equal to?
The body has a horizontal component of velocity ux=600km/hr and no vertical component uy=0.Also it has no horizontal component of acceleration ax=0 and ay=g.The horizontal distance x=uxt.We have to find out t.h=uyt+gt2/2=gt2/2or,t2=2h/gor,t=20s=1/180 hrSo x=uxt=600/180=10/3 km=3.33kmSo the distance AB=root(h2+x2)=root(19.62+3.332)=19.8 kmHope this helps.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -