badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

An aeroplane is flying in the horizontal direction with a velocity 600 km/hr at a height 1960 m. When it is vertically above a point A on the ground, a body is droppd from it. The body strikes a ground at point B. The distance AB is equal to?

2 years ago

Answers : (1)

Susmita
425 Points
							
The body has a horizontal component of velocity ux=600km/hr and no vertical component uy=0.
Also it has no horizontal component of acceleration ax=0 and ay=g.
The horizontal distance x=uxt.We have to find out t.
h=uyt+gt2/2=gt2/2
or,t2=2h/g
or,t=20s=1/180 hr
So x=uxt=600/180=10/3 km=3.33km
So the distance AB
=root(h2+x2)
=root(19.62+3.332)
=19.8 km
Hope this helps.
 
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details