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A weight of 2 kg suspended from the end of a wire of cross sectional area 20mm². Thedirection of the stress produced is upward.how? Please explain fully

sudhanva gv , 6 Years ago
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anser 1 Answers
Arun

Last Activity: 6 Years ago

Stress = Force/ Area.

Force= m x a .

Assuming a=g= 9.81 m/s^2.

Force= 9.81 N

Area of a circle= (3.14 * diameter^2)/4.

= 0.785 * (.02^2)

= 0.0003140 m^2.

Stress= 9.81/0.0003140

= 31242 N/m^2.

= 31242 Pa

= 124.9 kPa.

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