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`        A weight of 2 kg suspended from the end of a wire of cross sectional area 20mm². The  direction of the stress produced is upward.how? Please explain fully`
9 months ago

Arun
22034 Points
```							Stress = Force/ Area.Force= m x a .Assuming a=g= 9.81 m/s^2.Force= 9.81 NArea of a circle= (3.14 * diameter^2)/4.= 0.785 * (.02^2)= 0.0003140 m^2.Stress= 9.81/0.0003140= 31242 N/m^2.= 31242 Pa= 124.9 kPa.
```
9 months ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions