A variable line drawn through the intersection point of x + 2y = 1 and 2x-y = 1 meets x-axis at A and y-axis at B, then :- a ) locus of foot of perpendicular from the origin on AB is 5x^2+5y^2-3x-y=0 ;b) locus of perpendicular bisector of AB is 5x^2+5y^2+3x+y=0..The answer should be `a`..Please help.
Anagha Hebbar
10 Years agoGrade 11
1 Answer
Kunal
10 Years ago
Well if you wanna go by answer logic, B is obviously wrong because the centre of the circle lies in the 4th quadrant according to it. Lol.