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Grade: 12th Pass

                        

A uniform chain of mass 3m and length 3l is placed on a smooth pulley as shown. Due to slight disturbance right side chain has started to move down, then reaction of pulley when right side part of chain has length 3l/2

3 years ago

Answers : (1)

Arun
24735 Points
							
Weight of chain of length "x" =(M/Lx)g
 
Amount of work done in moving dx to the top
dW = F→. dx→
 
      =F.dx   = (MLx)gdx
 
The total amount of work done in moving the one third length of the hanging chain on the table will be
W=∫L/3 - 0 MLxgdx = M / Lg
 
∫L / 3 - 0 xdx
 
= M/ Lg[x^2 / 2] L/3 - 0
 
=MgL / 18
 
Hence the work required to pull the hanging part on the table is MgL / 18.
 
 
4 months ago
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