0

Guest

Courses New

A U tybe containing two different liquids fixed at vertically on rotating table aboutca vertical axis passing through centre of table. The interface of two liquids resp. Lies at A in U tube at rest, height of liquid column just above A is 8/3a. Cross sectional area of tube is S. Now table is whirled with angular velocity omega about vertical axis, such that interface of liquid shifts toward B by 2/3a. Then at this instant find Pa-Pb

A U tybe containing two different liquids fixed at vertically on rotating table aboutca vertical axis passing through centre of table. The interface of two liquids resp. Lies at A in U tube at rest, height of liquid column just above A is 8/3a. Cross sectional area of tube is S. Now table is whirled with angular velocity omega about vertical axis, such that interface of liquid shifts toward B by 2/3a. Then at this instant find Pa-Pb

Question Image
Grade:12

1 Answers

Vikas TU
14149 Points
4 years ago
Dear student
Equation of parabola
y = w^2x^2 /2g 
At A coordinates will be (L,h)
Substitute in equation 
h = w^2L^2 /2g

Think You Can Provide A Better Answer ?

Other Related Questions on IIT JEE Entrance Exam

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More