+91-87964 74404
FlagBACK
Question icon
Grade 11IIT JEE Entrance Exam

A trolley of mass 5 kg on a horizontal smooth surface is pulled by a load of mass 2 kg by means of uniform rope ABC of length 2m and mass 1kg .As the load falls from BC=0 to BC=2m .its acceleration in m/s2 changes

Profile image of Tejaswi
7 Years agoGrade 11
Answers icon

1 Answer

Profile image of Arun
6 Years ago
Initial force = 2 g = 20 N
 
Total mass = 5 +  = 6 Kg
 
BC = 2 m
 
Initial acceleration = Force Mass=20 / 5 + 1=20 / 6 ms−2
 
Final force = (Load + mass of thread)×g
 
                  = (2+1) ×10=30 N
 
Therefore, final acceleration =30 / 6 ms^−2.
 
Thus the acceleration changes from 30 / 6 ms^−2.
 
 

Other Related Questions on iit jee entrance exam

question mark

Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-

iit jee entrance exam
1 Answer Available

Last Activity: 10 Months ago

question mark
My rank is 29k, General, should I opt for any state college cse branch or some Nits in which in which I am getting ECE , chemical, mechanics etc....
 
iit jee entrance exam
1 Answer Available

Last Activity: 3 Years ago

question mark
How is Ranquer Eduzone,comparing, Akash,Fitjee,Resonance,Naryana
iit jee entrance exam
1 Answer Available

Last Activity: 4 Years ago

question mark
Can class 9th students study syllabus class  of 11th 
iit jee entrance exam
3 Answers Available

Last Activity: 4 Years ago

question mark
Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2....+[-1]^n[n+1]2Cn] where n is an even positive integer. Kindly provide solution of this question and how to generalise this. How do we know that which expansion will give this?
iit jee entrance exam
1 Answer Available

Last Activity: 4 Years ago