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A trolley of mass 5 kg on a horizontal smooth surface is pulled by a load of mass 2 kg by means of uniform rope ABC of length 2m and mass 1kg .As the load falls from BC=0 to BC=2m .its acceleration in m/s 2 changes
A trolley of mass 5 kg on a horizontal smooth surface is pulled by a load of mass 2 kg by means of uniform rope ABC of length 2m and mass 1kg  .As the load falls from BC=0 to BC=2m .its acceleration in  m/s2  changes

```
2 years ago

Arun
25768 Points
```							Initial force = 2 g = 20 N Total mass = 5 +  = 6 Kg BC = 2 m Initial acceleration = Force Mass=20 / 5 + 1=20 / 6 ms−2 Final force = (Load + mass of thread)×g                   = (2+1) ×10=30 N Therefore, final acceleration =30 / 6 ms^−2. Thus the acceleration changes from 30 / 6 ms^−2.
```
8 months ago
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• Test paper with Video Solution
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