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A trolley of mass 5 kg on a horizontal smooth surface is pulled by a load of mass 2 kg by means of uniform rope ABC of length 2m and mass 1kg.As the load falls from BC=0 to BC=2m .its acceleration inm/s2changes

Tejaswi , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 4 Years ago

Initial force = 2 g = 20 N
 
Total mass = 5 +  = 6 Kg
 
BC = 2 m
 
Initial acceleration = Force Mass=20 / 5 + 1=20 / 6 ms−2
 
Final force = (Load + mass of thread)×g
 
                  = (2+1) ×10=30 N
 
Therefore, final acceleration =30 / 6 ms^−2.
 
Thus the acceleration changes from 30 / 6 ms^−2.
 
 

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