badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A trolley of mass 5 kg on a horizontal smooth surface is pulled by a load of mass 2 kg by means of uniform rope ABC of length 2m and mass 1kg .As the load falls from BC=0 to BC=2m .its acceleration in m/s 2 changes

2 years ago

Answers : (1)

Arun
24742 Points
							
Initial force = 2 g = 20 N
 
Total mass = 5 +  = 6 Kg
 
BC = 2 m
 
Initial acceleration = Force Mass=20 / 5 + 1=20 / 6 ms−2
 
Final force = (Load + mass of thread)×g
 
                  = (2+1) ×10=30 N
 
Therefore, final acceleration =30 / 6 ms^−2.
 
Thus the acceleration changes from 30 / 6 ms^−2.
 
 
5 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details