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`        A train is approaching a platform with a speed of 10 km per hour when it is at a distance of 2 km from the platform brakes are applied so that a uniform retardation is produced at the same time a bird sitting on a pole near the platform price with a speed of 50 km per hour towards the train and touches the front of the train and comes back to the pole if the if the motion is repeated until the train comes back to rest the total distance travelled by the body isA 10 kmB 60 kmC 20 kmD 15 km`
one year ago

Arun
22545 Points
```							V^2 = u^2 – 2as using this v =0 and u=10km/hr s=2we get -100 = 2a(2)a=-25time to stop the train v=u +at 0=10 - 25tt=2/5hr so bird will travel for d distanced=vtd=50(2/5)d=20km
```
one year ago
Saurabh Koranglekar
3154 Points
```							V2=u2+2as0=100+2×a×2Hence a=-25km/hr2v=u+att= -10/(-25)= 2/5bird traveled for (2/5 hrs )@ 50km/hrdist coveredis 0.4*50 = 20 kmans c
```
one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions