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According to questions, there r 7 intermediate stations, this means they can have 8 different kind of tickets.
Note: J,1,2,3,..7,D are the stations
D->1, D->2,D->3,D->4...D->7,D->J
Then if the passengers have the tickets of the same class can may be of same stations, no of tickets possible are 85
However if they have tickets of different stations of same coach the permutations are 8*7*6*5*4
Regards
Arun
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