A thin equiconvex spherical glass lens (µ = 3/2) of radius of curvature 30 cm is placed on the x-axis with its optical centre at x = 40 cm and principal axis coinciding with the x-axis. A light ray given by the equation 39y = – x + 1 (x and y are in cm) is incident on the lens, in the direction of positive x-axis. The correct alternative(s) isA) equation of refracted ray is 39y=x-1B) equation of refracted ray is 130y=x-170C) equation of the refracted ray if space on the right side is filled with a liquid of refractive index 4/3 390y+x+350=0D)equation of the refracted ray if space on the right side is filled with a liquid of refractive index 4/3 390y-x+350=0
Vedant Juneja
8 Years agoGrade 12
1 Answer
Arun
6 Years ago
When air is on both sides of the lens,
20
1
−
−20
1
=
f
1
Hence,
f
1
=
10
1
=(μ
lens
−1)(
R
1
−
−R
1
)
Hence, R=10cm
2. When liquid is inside the vessel.
For the refraction from bottom side of the lens,
v
μ
g
−
u
μ
1
=
R
μ
g
−μ
1
hence
v
1.5
=
20
3−3μ
1
Now this v acts as an object for the refraction from top surface of the lens.