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`        A stress of 1kg/mm^-2  is applied to a wire which Young’s modulus is 10^11 Nm^-2 .Find the percentage incerease in length?`
3 years ago

SAHIL
3783 Points
```
We have,
F/A = 1 kg/mm2 = 106 kg/m2
Y = 1011 N/m2
Now,
Y = (F/A)/(ΔL/L)
=> (ΔL/L) = (F/A)/Y = 106/1011 = 10-5
Therefore, (ΔL/L) × 100% = 10-3 %
THANKS JAKIRA
KEEP POSTING

```
3 years ago
Bhomik Singh rana
11 Points
```							Sol^n-          F/A=9.8*10^-6            Y=10^11 Y=(F/A)/(l/L)(l/L)=9.8*10^-6/10^11      =9.8*10^5     Now,     = ( l/L)*100     =(9.8*10^-5)*100      =0.0098%
```
2 years ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions