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Grade: 12
        
A stress of 1kg/mm^-2  is applied to a wire which Young’s modulus is 10^11 Nm^-2 .Find the percentage incerease in length?
one year ago

Answers : (2)

SAHIL
3784 Points
							

We have,

F/A = 1 kg/mm2 = 106 kg/m2

Y = 1011 N/m2

Now,

Y = (F/A)/(ΔL/L)

=> (ΔL/L) = (F/A)/Y = 106/1011 = 10-5

Therefore, (ΔL/L) × 100% = 10-3 %

THANKS JAKIRA

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one year ago
Bhomik Singh rana
11 Points
							Sol^n-          F/A=9.8*10^-6            Y=10^11 Y=(F/A)/(l/L)(l/L)=9.8*10^-6/10^11      =9.8*10^5     Now,     = ( l/L)*100     =(9.8*10^-5)*100      =0.0098%
						
9 months ago
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