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A stone thrown upwards, has its equation of motion s=490t-4.9t^2 where 's' in metres and t in seconds respectively. what is the maximum height reached by it?
A stone thrown upwards, has its equation of motion s=490t-4.9t^2 where 's' in metres and t in seconds respectively. what is the maximum height reached by it?

```
3 years ago

Shivam Taneja
12 Points
```							Dear Ameya,see s=ut-0.5gt^2comparing this we get u=490thus for max hieght,v^2-u^2=2asv=0 at highest point and a=-9.8s=490*490/2/9.8 =490*25 =12250
```
3 years ago
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