A stone thrown upwards, has its equation of motion s=490t-4.9t^2 where 's' in metres and t in seconds respectively. what is the maximum height reached by it?

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Shivam Taneja · Answer

Dear Ameya, see s=ut-0.5gt^2 comparing this we get u=490 thus for max hieght, v^2-u^2=2as v=0 at highest point and a=-9.8 s=490*490/2/9.8 =490*25 =12250

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A stone thrown upwards, has its equation of motion s=490t-4.9t^2 where 's' in metres and t in seconds respectively. what is the maximum height reached by it?

A stone thrown upwards, has its equation of motion s=490t-4.9t^2 where 's' in metres and t in seconds respectively. what is the maximum height reached by it?

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A stone thrown upwards, has its equation of motion s=490t-4.9t^2 where 's' in metres and t in seconds respectively. what is the maximum height reached by it?

A stone thrown upwards, has its equation of motion s=490t-4.9t^2 where 's' in metres and t in seconds respectively. what is the maximum height reached by it?

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