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Grade: 11

                        

A stone thrown upwards, has its equation of motion s=490t-4.9t^2 where 's' in metres and t in seconds respectively. what is the maximum height reached by it?

3 years ago

Answers : (1)

Shivam Taneja
12 Points
							
Dear Ameya,
see s=ut-0.5gt^2
comparing this we get u=490
thus for max hieght,
v^2-u^2=2as
v=0 at highest point and a=-9.8
s=490*490/2/9.8
 =490*25
 =12250
3 years ago
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