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Grade 12th passIIT JEE Entrance Exam

A stone falls freely such that the distance covered by it in the last second of its motion is equal to the distance covered by it in the first 5 sec.it remain in air for

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Profile image of Riya
8 Years agoGrade 12th pass
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1 Answer

Profile image of Aman verma
8 Years ago
In first second it travels 5m and in every next second it travels 10m more so in 2 sec it travels 15m and like this in 13sec of its motion it travels 125m so we can se that it remains in air for 13 sec
       And we can also apply the formula 
            S=u + a/2(2n-1) it is the formula for distance travelled in nth second when n is no. Of seconds and a is acceleration and u is initial velocity.

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