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`        A spring of force constant K is cut into two parts of length in the ratio 1:2. spring constant of the larger one is`
11 months ago

Arun
22591 Points
```							 let length of the spring having spring constant k is L. now as spring is cut into 2 pieces .                                          L1= L/3                                           L2=2 x L/3   (as one piece is double of other in length) kL=k1 L1=k2 L2    kL=k2(2L/3)     3k/2=k2 therefore k2=3k/2 RegardsArun
```
11 months ago
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