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Grade 10IIT JEE Entrance Exam

A sphere of radius $R$ is in contact with a wedge. The point of contact is $\frac{R}{5}$ from the ground as shown in figure. Wedge is moving with velocity $20 towards left then the velocity of the sphere at this instant will be

Profile image of sinku nayak
8 Years agoGrade 10
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1 Answer

Profile image of Arun
6 Years ago
Assume for the moment that R= 5(it doesn't matter for the slope),
 
so the circle is given by x^2+y^2=25
 
Because height= R/5
 
We are looking for the slope of the tangent line through the point with y=-4
 
which is (-3,-4)
 
Now the slope is given by = -x/y= -3/4
 
=) Now, given a velocity of 20m/s to the left
 
We know that the sphere will have a velocity of 3/4× 20m/s
 
=) 15m/s
 
Thanks and regards

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