0

Guest

Courses New

A sphere of radius is in contact with a wedge. The point of contact is from the ground as shown in figure. Wedge is moving with velocity towards left then the velocity of the sphere at this instant will be

A sphere of radius $R$ is in contact with a wedge. The point of contact is $\frac{R}{5}$ from the ground as shown in figure. Wedge is moving with velocity $20 m/s$ towards left then the velocity of the sphere at this instant will be

Grade:10

1 Answers

Arun
25750 Points
3 years ago
Assume for the moment that R= 5(it doesn't matter for the slope),
 
so the circle is given by x^2+y^2=25
 
Because height= R/5
 
We are looking for the slope of the tangent line through the point with y=-4
 
which is (-3,-4)
 
Now the slope is given by = -x/y= -3/4
 
=) Now, given a velocity of 20m/s to the left
 
We know that the sphere will have a velocity of 3/4× 20m/s
 
=) 15m/s
 
Thanks and regards

Think You Can Provide A Better Answer ?

Other Related Questions on IIT JEE Entrance Exam

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More