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A solution of Coastic Soda having specific gravity 1.32 contain 28.8% NaOH. What volume of H2SO4 of specific gravity 1.8 which contains 99% of pure H2SO4 would be required to neutralize 1.5 L of Coastic Soda Solution?
Please answer fast. Help needed.

Tejas Mahadik , 6 Years ago
Grade 11
anser 1 Answers
Arun
1000 mL will weigh 1800g
mass of H2SO4 present = 1800 gm
number of mole of H2SO4 = actual mass/molarmass= 1800 ÷   98 = 18.36
thus molarity of a stock solution is 18.36 M
To prepare 500 mL of 0. 9 M solution, M1V1=M2V2
18.36 x A = 0.9 x 500 mL
18.36450
= 24.5 ml 
Last Activity: 5 Years ago
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