Arun
Last Activity: 4 Years ago
Let r be the radius of the water drop formed.
Since the volume of the water forming bubble and drop is same,34π(R3−(R−d)3)=34πr3
⟹r3≈3R2d (neglecting d2 and d3)
Ratio of excess pressure in the drop to the excess pressure inside the bubble is given by,
Ratio=4σ/R2σ/r
Ratio=21(rR)
Substituting the value of r gives (24dR)1/3