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A simple pendulum is vibrating with an angular amplitude of 90 o as shown in the figure. For what value of x (angle between string and verticle) during its motion, the total acceleration is directed horizontally?
Acceleration of a simple pendulum is a=−ω 2 ×A×cos(ωt+θ), where ω is angular velocity, A is amplitude, t is time and θ is angle.If θ is 0, then a=−ω 2 ×A×cos(ωt) so direction is vertically upwards, when θ is cos −1 (1/3 1/2 ) then direction is horizontally, when θ is 90 o , then a=ω 2 ×A×sin(ωt) so direction is vertically downwards.
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