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Grade 12th passIIT JEE Entrance Exam

a short dipole is situated at the origin of coordinate axis with its axis along x-axis and equator along y-axis . It is found that the magnitudes of the elecric intensity and electric potential due to dipole are equal at a point distant r = root 5 from origin, Find the position vector of the point

Profile image of Devesh
7 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
6 Years ago
Dear student 
|Ep| = |Vp| 
Kp/r^3 sqrt(1+3cos^2Q) 
= KpCosQ /r^2
Q = 45 degree 
r = sqrt(5/2) (i+j)
Good luck