a short dipole is placed at a distance x from centre O on the axis of a ring of radius R and charge Q is uniformly distributed over it.
the net force acting on the dipole is?

Question

a short dipole is placed at a distance x from centre O on the axis of a ring of radius R and charge Q is uniformly distributed over it. the net force acting on the dipole is?

rajula vineet reddy · Answer

the answer is F=2Qp/((R^2+x^2)^3/2) where pis the dipole moment.

ria · Answer

its the wrong answer..... i wasnt even amng d options.... answer is KQP (R^2 - 2x^2 ) / (R^2 + x^2) ^5/2

ria · Answer

hey if u could just tell me dat how woul u differentiate x/ (R^2 +X^2) wrt X

rajula vineet reddy · Answer

ya the answer is KQP(R^2-2x^2)/(R^2+x^2)^5/2 use the formula F=p(dE/dx) and use d/dx (u/v) form......

ria · Answer

thnx

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

a short dipole is placed at a distance x from centre O on the axis of a ring of radius R and charge Q is uniformly distributed over it. the net force acting on the dipole is?

a short dipole is placed at a distance x from centre O on the axis of a ring of radius R and charge Q is uniformly distributed over it.
the net force acting on the dipole is?

5 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on IIT JEE Entrance Exam

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship