Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A Ray of light starting from (3,10) hits The Mirror 2 X +3y -6=0 and passes through the point (7,2) after reflection. The equation of reflected Ray is`
one year ago

## Answers : (1)

1807 Points
```							rather than taking the long route and finding the point of intersection of the line with the mirror, you can instead use a clever trick. simply find the reflection of the point  (3,10) in The Mirror 2 X +3y -6=0. lets call the reflection as point C. then write the eqn of line joining point C and (7,2). and there you have it, equation of the reflected Ray!
```
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on IIT JEE Entrance Exam

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions