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A projectile is thrown with a velocity of 10Root2 m/s at an angle of 45 degrees with horizontal. The interval between the moments when speed is root125 m/s
Need to find : The time interval between the moments when the speeds are √125 m/s projectile is thrown with a velocity of 10√2 m/s angle of 45° Horizontal Velocity = 10√2Cos45 = 10 m/s Vertical Velocity = 10√2Sin45 = 10 m/s Horizontal Velocity will remain constant = 10 Let say at time t the Velocity = √125 m/s => Vertical Velocity² + Horizontal Velocity² =( √125 )² => Vertical Velocity² + 10² = 125 => Vertical Velocity² = 25 => Vertical Velocity = ±5 Applying V = U + at 5 = 10 + (-10)t => t = 0.5 sec -5 = 10 + (-10)t => t = 1.5 sec √125 m/s velocity would be at t =0.5 sec & 1.5 sec Time interval between = 1.5 - 0.5 = 1 sec
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