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A projectile is thrown with a velocity of 10Root2 m/s at an angle of 45 degrees with horizontal. The interval between the moments when speed is root125 m/s

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2 years ago

Arun
25768 Points
```							Need to find : The time interval between the moments when the speeds are √125 m/s projectile is thrown with a velocity of 10√2 m/s angle of 45° Horizontal Velocity = 10√2Cos45  = 10 m/s Vertical Velocity = 10√2Sin45  = 10 m/s Horizontal Velocity will remain constant = 10 Let say at time t the Velocity = √125 m/s => Vertical Velocity² + Horizontal Velocity² =( √125 )² => Vertical Velocity²  + 10² = 125 => Vertical Velocity² = 25 => Vertical Velocity = ±5 Applying V = U + at 5 = 10 + (-10)t => t = 0.5 sec -5 = 10  + (-10)t => t = 1.5 sec √125 m/s velocity would be at t =0.5 sec & 1.5 sec Time interval between = 1.5  - 0.5 = 1 sec
```
7 months ago
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